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Allow filtering issues by any assignee (#33343)

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This is the opposite of the "No assignee" filter, it will match all
issues that have at least one assignee.

Before
![Before
change](https://github.com/user-attachments/assets/4aea194b-9add-4a84-8d6b-61bfd8d9e58e)

After
![After change with any
filter](https://github.com/user-attachments/assets/99f1205d-ba9f-4a0a-a60b-cc1a0c0823fe)

---------

Co-authored-by: wxiaoguang <wxiaoguang@gmail.com>
This commit is contained in:
Andreas Svanberg
2025-03-21 05:25:36 +01:00
committed by GitHub
parent a4df01b580
commit 0da7318cf3
22 changed files with 167 additions and 101 deletions
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6
modules/indexer/issues/dboptions.go
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@@ -45,11 +45,7 @@ func ToSearchOptions(keyword string, opts *issues_model.IssuesOptions) *SearchOp
searchOpt.ProjectID = optional.Some[int64](0) // Those issues with no project(projectid==0)
}
if opts.AssigneeID.Value() == db.NoConditionID {
searchOpt.AssigneeID = optional.Some[int64](0) // FIXME: this is inconsistent from other places, 0 means "no assignee"
} else if opts.AssigneeID.Value() != 0 {
searchOpt.AssigneeID = opts.AssigneeID
}
searchOpt.AssigneeID = opts.AssigneeID
// See the comment of issues_model.SearchOptions for the reason why we need to convert
convertID := func(id int64) optional.Option[int64] {